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More Useful Circuits

The linear and negative feedback circuits in National Semiconductor's AN-31 and on the other page are relatively common.
But also useful are open circuit op-amps and positive feedback which is analyzed in a slightly different way.

Consider the circuit below, part of a larger schematic for an embedded system.
This circuit uses an open loop op-amp to control a selector switch.
The selector switch, a FET in this example, connects the USB power to the internal 5 Volt rail when necessary. Positive Feedback Amplifier
So, How does this work and how do you analyze it?
First, the op-amp IC1B is set up in the classic unity gain buffer, so that analysis is completed.
Second, IC1A is open loop thus the equation VOUTPUT = AV*(Vp -Vm) applies. where: Third, notice that the positive input is the output of a Voltage Divider. Since the divider resistors are equal, the division is by 2.

Okay, what do I have so far?

At what input value does VOUTPUT reach the upper rail?
If VOUTPUT is 5V {the upper rail}, (Vp-Vm) = VOUTPUT/AV thus: Thus, so long as VIN is greater than 6.60066666V then VOUTPUT is at the upper rail.
From a VIN of 6.60066666V to 6.6000000V, the VOUTPUT is linearly related to VIN.
For a VIN of 6.6000000V and below, the VOUTPUT is zero

Why is this important?
To answer this we need to look at the FET.
The FET is an FQPF7P06, it is a enhancement mode, P-Channel device. Normally OFF. The Vgs (gate source) Threshold voltage is between -2 and -4 volts, so the gate has to be 2.0 to 4.0 Volts below +5V to turn ON the FET.
What is not shown in this schematic is that +5V is generated from VIN with a 7805 regulator.
This regulator typically requires an input of 2.0 Volts above the output, or 7.0V, to regulate.
Finally, if the input voltage VIN is less than 6.6 V the VOUTPUT is 0.0 V. Thus if the input voltage is too low the circuit will automatically switch to run of the USB power.

Now, in a case for absolute simplicity the unity gain buffer is not necessary. Potentially it could be deleted.
This op-amp is a two per package device.
Any unused op-amps must to have the input pins connected to ground to prevent noisy oscillations from starting.
It is just as easy to connect this amplifier up as a unity gain amplifier as to connect both input pins to ground.

What about the resistive divider?
Positive Feedback Amplifier
For a complete explanation of the E96 Series see this site.
The original divider is a 10k Ohm and a 10k Ohm resistor.
The analysis above shows that the value one of the resistors would be better at 11k or 11.3k.
What are the reasons for or against changing to the 11.3k resistor?
For changing to 11.3k Ohm resistor: Against changing to 11.3k Ohm resistor: Most of the arguments against using the 11.3k value could be eliminated if
there are other values already used in the design that could be used to make up the 1.3k difference.
For example in the original design 1.00k Ohm resistors are also used,
so a 1.00k Ohm could be added in series with the upper 10.0k Ohm without too much trouble.

Provided that ... A full tolerance study still needs to be completed before this goes to lay out,
but that is left as an exercise for the student.

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